The two wires shown in the figure below are separated by d = 11.0 cm and carry c

Question

The two wires shown in the figure below are separated by d = 11.0 cm and carry currents of I = 5.10 A in opposite directions.

(a) Find the magnitude and direction of the net magnetic field at a point midway between the wires. magnitude ? µT

(b) Find the magnitude and direction of the net magnetic field at point P1, 11.0 cm to the right of the wire on the right. magnitude ? µT

(c) Find the magnitude and direction of the net magnetic field at point P2, 2d = 22.0 cm to the left of the wire on the left. magnitude ? µT

Explanation / Answer

There is no figure given.

I'll solve this assuming the left wire is up and the right wire is down. If this is not the case basically the magnitude will be the same but the direction will be opposite

In my case both fields will be into the page and will have the same magnitude

So B = 2*(o*I/2r) = (but o/2 = 2 X 10^-7)

so B = 2*(2 x 10^-7 x 5.20) / (0.11 / 2) = 3.78 x 10^-5 T (IN)

b)

b) Here the left wire creates a field into the page and the right wire is out

so the net field will be IN

B = o/2*(I1/0.11 - I2/(0.11 + 0.11))

B = 2 x 10^-7*(5.20 /0.11 - 5.20/(0.11 + 0.11)

B = 2 x 10^-7*(47.27 - 23.63)

B = 4.728 x 10^-6 T (IN)

C)

Now the net field will be OUT

B = o/2*(I1/0.11 - I2/(0.11 + 0.22))

B = 2 x 10^-7*(5.20/0.22 - 5.20/(0.11 + 0.22)

B = 2 x 10^-7*(23.63 - 15.76)

B = 1.574 x 10^-6 T (OUT)

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