A tiny dust particle (m- 2.70 x105 kg) has a charge of 2.15 x104 C when it enter

Question

A tiny dust particle (m- 2.70 x105 kg) has a charge of 2.15 x104 C when it enters an MRI machine with a speed of 7.02 m/s. The machine's strong magnetic field (B 2.50 T) and the particle are shown in the diagram. The field points out of your screen. Answer the three questions below, using three significant figures. Part A: Which path will the particle take while inside the field? A (straight through) B (curl to the left) O O (curl to the right) D(curl out of the screen - not pictured) E (curl into the screen - not picture) E (our into the screen- not picture Part B: What is the magnitude of the force (F) acting on particle? Number Part C: What would be the radius of curvature (r) of the particle as it travels through the magnetic field? Number

Explanation / Answer

Since magnteic field in out of page and being a positice charge

a positive charge deflects to the left

option B it is

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magnetic force F = qv B

F = (2.15 e -4 * 7.02 * 2.5)

F = 3.37 *10^-3 N

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radius r = mv/qB

r = (2.7 e -5 * 7.02)/(2.15 e -4 * 2.5)

r = 35.2 cm

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