A worker wants to turn over a uniform 1270-N rectangular crate by pulling at 53.

Question

A worker wants to turn over a uniform 1270-N rectangular crate by pulling at 53.0 ? on one of its vertical sides (the figure (Figure 1) ). The floor is rough enough to prevent the crate from slipping.
Part A
What pull is needed to just start the crate to tip?

P =
N

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Part B
How hard does the floor push on the crate?

N =
  N

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Part C
Find the friction force on the crate.

f =
  N

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Part D
What is the minimum coefficient of static friction needed to prevent the crate from slipping on the floor?

?s =

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Explanation / Answer

sum of torque = 0

P(1.5) *sin53 - w(1.10) = 0

w = 1270

P = 1166.156 N

part b )

sum of force in y direction = 0

n-w-Pcos53 = 0

n = w + Pcos53 = 1971.81 N

part c )

sum of Fy = 0

fs = Psin53 = 931.33 N

part d )

us = fs/n

us = 0.382

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