The mass of a particular eagle is twice that of a hunted pigeon. Suppose the pig

Question

The mass of a particular eagle is twice that of a hunted pigeon. Suppose the pigeon is flying north at 16.7 m/s, when the eagle swoops down, grabs the pigeon, and flies off. At the instant right before the attack, the eagle is flying toward the pigeon at an angle Q = 58.3 degree below the horizontal, and a speed of 38.5 m/s. What is the speed of the eagle immediately after it catches its prey? What is the magnitude of the angle, measured from horizontal, at which the eagle is flying immediately after the strike?

Explanation / Answer

let

m1 = 2*m

u1 = 38.5 m/s

m2 = m

u2 = 16.7 m/s

let Vx and Vy are components of velocity of eagle after attach.

apply conservation of momentum in x-direction.

m1*u1x + m2*u2x = (m1+m2)*vx

==> vx = (m1*u1x + m2*u2x)/(m1+m2)

= (2*m*38.5*cos(58.3) + m*16.7)/(2*m+m)

= 19.05 m/s

apply conservation of momentum in y-direction

m1*u1y + m2*u2y = (m1+m2)*vy

==> vy = (m1*u1y + m2*u2y)/(m1+m2)

= (2*m*38.5*sin(58.3) + 0)/(2*m+m)

= 21.8 m/s

so, v = sqrt(vx^2 + vy^2)

= sqrt(19.05^2 + 21.8^2)

= 28.95 m/s <<<<<<<<<<<<<<<<<<<<<<<--------Answer

angle made by eagle with horizontal,

theta = tan^-1(vy/vx)

= tan^-1(21.8/19.05)

= 48.85 degrees <<<<<<<<<<<<<<<<<<<<<<<--------Answer

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.