answer ALL questions please Introductory Biology- Population Genetics Problem Se
ID: 145173 • Letter: A
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answer ALL questions please
Introductory Biology- Population Genetics Problem Set I. Suppose that you study the genetices of a locus that controjs flower color (C). There is no dominance and homozygous CR give red flowers, homozygous C give white flowers and the heterozy gotes are pink. You go out and write down the phenotypes of a number of plants and get the following: rf red 70 ww pink:# 120 r white 110 (a) What are the allele frequencies in the study population? (b) Is this population at Hardy-Weinberg Equilibrium? 2 Suppose that the following frequencies are observed for blood type alleles in a human population: I 0.40 IB 0.05 i 0.55 (a) Write and expand an equation to predict the frequency of each genotype at Hardy- Weinberg equilibrium. (b) If the population is at Hardy-Weinberg equilibrium, give the frequency of each of the following: (i) type "O" individuals (ii) A blood types who are homozygotes (ii) total proportion who have type A blood (iv) frequency of type AB (c) What will the frequencies be of alleles IA, IB, and i in the next generation? How a type O? What will be the frequency of each aliele and type O in three more generations? 3. Suppose that you know a population is at or very close to H-W equilibrium with count individuals with the two different phenotypes and find: Phenotype A respect to a certain locus. Furthermore, assume that this locus, called A, shows complete dominance with only two alleles present (the dominant and recessive). Suppose that you 125 375 Phenotype a (a) What are the frequencies of the two phenotypes? (b) What genotypes make up each phenotype?Explanation / Answer
red= 70, homozygous Cr
pink=120 heterozygous
white=110 homozygous
Total number= 300
heterozygous=120/300=0.4
0.4/2=0.2
total Allele frequency of red= 70/300=0.23+0.2=0.43
total Allele frequency of white= 110/300=0.36+0.2=0.56
2a) p2+q2+2pq=1
where p and q are the frequencies of dominat and recessive allleles,
p2= number of homozygous dominant individuals
q2=number of homozygous recessive individuals
2pq= heterozygous individuals
p+q=1
2b) As per the information given in the question
IA= 0.40
IB=0.05
i=0.55
i) O BLOOD GROUP= io*io= 0.55*0.55=0.3025
ii homozygous)A blood group= IA*IA= 0.4*0.4=0.16
iii) total A blood types= 0.16+ AB type/2
= 0.16+0.01= 0.17
iv) AB blood type=IA*IB= 0.40*0.05
=0.02
3) Phenotype A= 125
125/(375+125)= 125/500= 0.25
PHENOTYPE AA= genotypic frequency=p2=0.25 so p= 0.5
p+q=1
q=1-p=1-0.5=0.5
a)phenotypic freq= 0.5 since only two phenotypes exist.
b) genotypes that make a phenotype will be AA and aa.
Phenotype a= 375= 375/0.75
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