Four forces of equal magnitude act along the sides of a square as shown in Fig.

Question

Four forces of equal magnitude act along the sides of a square as shown in Fig. 1. Determine the resultant force F vector if |F vector_1| = F vector_2| = F vector_3| = F vector_4| = 2 lbs. Assume that each side of the square has a length of 2 meters. FIG. 1: Four forces of equal magnitude acting at the at the corners of a box. F vector = Squareroot 32x + Squareroot y, with a line of action connecting the origin to the opposite corner. F vector = 4x + 4y, with a line of action connecting the origin to the opposite corner. F vector = (1/Squareroot) x + (1/Squareroot) y, with a line of action connecting the origin to the opposite corner. F vector = Squareroot 32x + Squareroot y, with a line of action connecting the origin to the point (x = 2, y = 0). F vector = Squareroot x + Squareroot y, with a line of action connecting the origin to the point (x = 0, y = 2).

Explanation / Answer

force in x direction = F1 + F2 = 4xi

force in ydirection = F3 + F4 = 4yj

direction = origin to the opposite corenr

F = 4xi + 4yj

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