An aluminum calorimeter with a mass of 100 g contains 250 g of water. The calori

Question

An aluminum calorimeter with a mass of 100 g contains 250 g of water. The calorimeter and water are in thermal equilibrium at 10.0 degree C. Two metallic blocks ore placed into the water. One is a 150.0-q piece of copper at 40.0 degree C. The other has a mass of 70.0 g and is originally at a temperature of 100degreeC. The entire system stabilizes at a final temperature of 20.0degreeC. Determine the specific heat of the unknown sample. Using the data in the table above, can you make a positive identification of the unknown material? Can you identify a possible material? Explain your answers for part (b).

Explanation / Answer

the whole system is at equilibrium at 20 C

heat energy balance

hear gained by water and aluminium calorimeter = 0.25*4186*10 + 0.1*900*10 = 10465+900 = 11365J

heat lost by copper = 0.15*387*20 = 1161.

heat lost by unknown material = 0.07*C*80 = 5.6C

total heat lost = 5.6C + 1161 = 11365

C = 1822.14 J/kg.C

b) From the table, the specific heat of materials close to the specific heat calculated is Beryllium = 1830

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