One force acting on a machine part is F ? =(?5.00N) i ^+(4.00N) j ^. The vector

Question

One force acting on a machine part is F? =(?5.00N)i^+(4.00N)j^. The vector from the origin to the point where the force is applied is r? =(?0.450m)i^+(0.150m)j^.

Use the right-hand rule to determine the direction of the torque.

Calculate the torque produced by this force.

Exercise 10.5 Part A One force acting on a machine part is F = (-5.00 N)i + (4.00 N)]. The vector from the origin to the point where the force is applied is r = Use the right-hand rule to determine the direction of the torque. | OInto the plane of the page. OOut of the plane of the page. (-0.450 m)i + (0.150 m); Submit My Answers Give Up Part B Calculate the torque produced by this force. N-m Submit My Answers Give Up

Explanation / Answer

F = -5i + 4j
r = -0.45i + 0.15j
T = r x F = [-0.45i + 0.15j]x[-5i + 4j] = -1.8k + 0.75k = -1.05 k Nm

1. Direction : into THE PLANE OF PAGE
2. |t| = 1.05 nM

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.