UNiversity Physics Test#2 Name 1) A 14-A current flows i the 3.0- resistor? into
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Question
UNiversity Physics Test#2 Name 1) A 14-A current flows i the 3.0- resistor? into a parallel combination of a 30.0 What current flows through A) 8.0 A B) 6.0 A D) 24 V E) 5.0 A 2) An electric device delivers a current of 3.0 A for 10 sconds y electrons flow through this device? A) 20 9 x 1020 D) 2.0 E) 0.20 angle of 60 with the respect to a magnetic field of st Bnitude of the magnetic force acting on the wire? 3) A wire carrying a 2-A current is placed at tic field of strength 0.2T. the length of the wire is 0.6 m what is the magnitude of the B) 1.0 N A) 0.8 N D) 0.2 N E) 04N 4) What is the maximum current that can be drawn from a 1.50- B) 4.5 A rawn from a 1.50-V battery with an internal resistance of o E) 5.0 A AAN) of 0.30 ohm? A) 2.5 A D) 0.20 A 5) A 4000- resistor is connected across 220 V. what current will B) 18 A A) 5.5 A D) 1.8 A E) 550 A C)0055 A 6) A high power line carrying 1000 A generates what magnetic field at the ground, 10 m away? D)47. 10-6T 32.10-6T A) 6.4 x 10-6 T B) 5.6 10-5 T 10-5T D)4.7 10-6T E32 10-6T 7) A 2.0-m wire carrying a current of 0.60 A is orient ndicular to a uniform magnetic field of 0.50 T. What is the magnitude of the force it experiences? A) 0.50 N B) 0.30 N D) zero E) 0.60 N C) 0.15 N 8) How much energy does a 100-W light bulb use in 80 hours? C) 0.80 kWh A) 13 kWh B) 0.0080 kWh D) 800 kWh E) 130 kWh 9) A solenoid with 500 turns has a radius of 0.040 m and is 40 cm long. If this solenoid carries a current of 12 A, what is the magnitude of the magnetic field at the center of the solenoid? A) 19 mT B) 16 mT C)9.0 mT D) 4.9 ml E) 6.0 mT 10) A 2-m long wire is carrying a current of 2 A. The wire is placed at an angle of 60° with respect to a magnetic field. If the wire experiences a force of 0.2 N, what is the strength of the magnetic field? A) 0.04 T B)0.05 T 06 T D) 0.02T E) 0.03T 11) Three resistors of 12, 12, and 6.0 are connected in series. A 12-V battery is connected to the combination. What is the current through the 60- resistor? A) 0.60 A B) 0.80 A C) 0.40 A D) 0.20 A E) 1.0A 12) A light bulb operating at a voltage of 120 V has a resistance of 200 , what is the power? D) 14x10-3 w A) 100 W B) 7.2 W E)72 WExplanation / Answer
1. Current in parallel resistors in inversely proportional to resistance.
R1=3ohm
R2=4ohm
I=14A
I1/I2=R2/R1= 4/3.
I1+I2=14
3I1=4I2
so so using both 7/4 I1=14 so I1=8 A
3. F = B x I x L x sin theta
where F is the force acting on the length of wire (in Newtons [N]).
where B is the magnetic field strength/magnetic flux density (in Tesla [T]).
where I is the current going through the length of wire (in Amps [A]).
where L is the length of the wire (in metres [m]).
where sin theta is the sin of the angle the length of wire is to the magnetic field.
F = 2 x 2 x 0.6 x sin (60)
F=.2N
4.V=IR
so I=V/R puting in values we gwt I=5.0N
5.V=IR So I=V/R putting in values we get I=.055N
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