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(a) What is the x -component of the electric force exerted by A on C ? N (b) Wha

ID: 1454163 • Letter: #

Question

(a) What is the x-component of the electric force exerted by A on C?
N

(b) What is the y-component of the force exerted by A on C?
N

(c) Find the magnitude of the force exerted by B on C.
N

(d) Calculate the x-component of the force exerted by B on C.
N

(e) Calculate the y-component of the force exerted by B on C.
N

(f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C.
N

(g) Repeat part (f) for the y-component.
N

(h) Find the magnitude and direction of the resultant electric force acting on C.

magnitude N direction ° counterclockwise from the +x-axis

Explanation / Answer

Let

qA = 4*10^-4 C

qB = -8*10^-4 C

qC = 2*10^-4 C

a) FAC = k*qA*qC/dAc^2

= 9*10^9*4*10^-4*2*10^-4/4^2

= 45 N

FACx = 0 N

b) FACy = 45

c) |FAC| = 45 N

d) FBC = k*qB*qC/dBC^2

= 9*10^9*8*10^-4*2*10^-4/(2^2+4^2)

= 72 N

FBCx = FBC*cos(theta)

= 72*4/sqrt(2^2+4^2)

= 64.4 N

e) FBCy = -FBC*sin(theta)

= -72*2/sqrt(2^2+4^2)

= -32.2 N

f) FCx = FACx + FBCx

= 0 + 64.4

= 64.4 N

g) FCy = FAcy + FBCy

= 45 - 32.2

= 12.8 N

h) FnetC = sqrt(Fcx^2 + FCy^2)

= sqrt(64.4^2 + 12.8^2)

= 65.6 N

direction : theta = tan^-1(FCy/Fcx)

= tan^-1(12.8/64.4)

= 11.24 degrees