(a) What is the x -component of the electric force exerted by A on C ? N (b) Wha
ID: 1454163 • Letter: #
Question
(a) What is the x-component of the electric force exerted by A on C?
N
(b) What is the y-component of the force exerted by A on C?
N
(c) Find the magnitude of the force exerted by B on C.
N
(d) Calculate the x-component of the force exerted by B on C.
N
(e) Calculate the y-component of the force exerted by B on C.
N
(f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C.
N
(g) Repeat part (f) for the y-component.
N
(h) Find the magnitude and direction of the resultant electric force acting on C.
Explanation / Answer
Let
qA = 4*10^-4 C
qB = -8*10^-4 C
qC = 2*10^-4 C
a) FAC = k*qA*qC/dAc^2
= 9*10^9*4*10^-4*2*10^-4/4^2
= 45 N
FACx = 0 N
b) FACy = 45
c) |FAC| = 45 N
d) FBC = k*qB*qC/dBC^2
= 9*10^9*8*10^-4*2*10^-4/(2^2+4^2)
= 72 N
FBCx = FBC*cos(theta)
= 72*4/sqrt(2^2+4^2)
= 64.4 N
e) FBCy = -FBC*sin(theta)
= -72*2/sqrt(2^2+4^2)
= -32.2 N
f) FCx = FACx + FBCx
= 0 + 64.4
= 64.4 N
g) FCy = FAcy + FBCy
= 45 - 32.2
= 12.8 N
h) FnetC = sqrt(Fcx^2 + FCy^2)
= sqrt(64.4^2 + 12.8^2)
= 65.6 N
direction : theta = tan^-1(FCy/Fcx)
= tan^-1(12.8/64.4)
= 11.24 degrees
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