The magnetic field in la increases uniformly from 0 to 1.5 T in 10 s. The circul
ID: 1454547 • Letter: T
Question
The magnetic field in la increases uniformly from 0 to 1.5 T in 10 s. The circular loop of copper wire (pcu = 1.7 times 10^-8 ohmm) has a radius of 0.1 m and the wire itself has a radius of 0.001 m. Determine the total charge that passes by a point in the wire during that 10 s. Would your answer change if it took 20 s to change from 0 to 1.5 T instead? Explain in words. b: As further proof of assume that the flux through the loop changes from_B(0) to_B(t) in a time t. Determine the charge that passes a particular point in that loop of resistance R during that time t.Explanation / Answer
resistance of the wire, R = rho*L/A
= 1.7*10^-8*2*pi*0.1/(pi*0.001^2)
= 3.4*10^-4 ohms
induced emf = A*dB/dt
induced ecurrent, I = induced emf/R
= A*(dB/dt)/R
we know, I = dQ/dt
==> dQ = I*dt
= A*(dB/dt)/R *dt
= A*dB/R
= pi*0.1^2*(1.5-0)/(3.4*10^-4)
= 138.6 C <<<<<<<<-----------------------Answer
No, because in the final expression we not have time term.
b) induced emf = (phi_Bt - phi_Bo)/t
induced current, I = induced emf/R
= (phi_Bt - phi_Bo)//(t*R)
Appli
i = Q/t
==> Q = I*t
= (phi_Bt - phi_Bo)/(t*R) *t
= (phi_Bt - phi_Bo)/R <<<<<<<<-----------------------Answer
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