A 0.60 kg ball is thrown with a speed of 15 m/s at an angle of 29 . Part A What

Question

A 0.60 kg ball is thrown with a speed of 15 m/s at an angle of 29 .

Part A

What is its speed at its highest point?

Express your answer using two significant figures.

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Correct

Part B

How high does it go? (Use conservation of energy, and ignore air resistance.)

Express your answer using two significant figures.

A 0.60 kg ball is thrown with a speed of 15 m/s at an angle of 29 .

Part A

What is its speed at its highest point?

Express your answer using two significant figures.

13

SubmitMy AnswersGive Up

Correct

Part B

How high does it go? (Use conservation of energy, and ignore air resistance.)

Express your answer using two significant figures.

Explanation / Answer

(a)

The velocity of the ball at top is,

vtop = v cos29 = 15 cos 29 = 13.12 m/s

(b)

Maximum height reached by the ball is,

     H = v^2 / 2g

    H = 15 ^2 / 2*9.8

H = 11.5 m

H = 12 m

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