Two wires parallel to each other and seperated by a distance d carry different c
ID: 1455001 • Letter: T
Question
Two wires parallel to each other and seperated by a distance d carry different currents; they exert a force with magnitude F on each other.
(a) The wires carry current in the same direction. If the current carried by both wires is quintupled and the distance between the wires is quintupled, then what will the force's magnitude be (as a multiple of F) and will it be repulsive or attractive?
F ---Select--- attractive repulsive
(b) The wires carry current in opposite directions. If the current carried by one of the wires is tripled and the distance between the wires is tripled, then what will the force's magnitude be (as a multiple of F) and will it be repulsive or attractive?
Explanation / Answer
We know that force between two infinite wire is given by F=u0*i1*i2/2*pi*d
(A)When i1, i2 and d is quintupled.
F'=u0*5i1*5i2/2*pi*5d
F'=5F
Since the current flows in same direction so the force will be attractive.
(B)When i1 and d is tripled.
F'=u0*3i1*i2/2*pi*3d
F'=F
Since the current in the wires are flowing in opposite directions so the force will be repulsive.
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