You have prepared a cell suspension of mouse lymph node cells (10 ml total in yo

Question

You have prepared a cell suspension of mouse lymph node cells (10 ml total in your tube) and now wish to determine the concentration of cells using a hemacytometer. You perform a 1/10 dilution, and put a sample in the hemacytometer, You count two of the large (1mm x 1mm) squares and find a total of 147 live cells and 15 dead cells. (3 pts) a. What is your concentration of live lymph node cells per milliliter? b. How many total live lymph node cells are present in your tube? c. What is the percent viability of your cells?

Explanation / Answer

concentrations are follow this

the total viable cells node are 147 are in susp.

10000 multyply this

147×10000=1470000

and dilutions are 0.1 so agan multyply this 0.1

and total concentrations are

1470000×0.1=147000

and total ml in susp tube

147000=147000 live cells/ml

2.

total ml is 10 ml in cells

total cells are 147000×10=1470000 live cells

3.

total viability are is

total cell= live cells +dead cells

1470000+15000=1620000 total cells

viability percent

150000÷1620000=0.926×100=92%

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