When viewing a piece of art that is behind glass, one often is affected by the l
ID: 1455426 • Letter: W
Question
When viewing a piece of art that is behind glass, one often is affected by the light that is reflected off the front of the glass (called glare), which can make it difficult to see the art clearly. One solution is to coat the outer surface of the glass with a thin film to cancel part of the glare.
Part A
If the glass has a refractive index of 1.64 and you use TiO2, which has an index of refraction of 2.62, as the coating, what is the minimum film thickness that will cancel light of wavelength 520 nm ?
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Part B
If this coating is too thin to stand up to wear, what other thicknesses would also work? Find only the three thinnest ones.
Enter your answer as three numbers separated with commas.
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When viewing a piece of art that is behind glass, one often is affected by the light that is reflected off the front of the glass (called glare), which can make it difficult to see the art clearly. One solution is to coat the outer surface of the glass with a thin film to cancel part of the glare.
Part A
If the glass has a refractive index of 1.64 and you use TiO2, which has an index of refraction of 2.62, as the coating, what is the minimum film thickness that will cancel light of wavelength 520 nm ?
t = nmSubmitMy AnswersGive Up
Part B
If this coating is too thin to stand up to wear, what other thicknesses would also work? Find only the three thinnest ones.
Enter your answer as three numbers separated with commas.
t2, t3, t4 = nmSubmitMy AnswersGive Up
Explanation / Answer
formula for minium thickness is
2nt = m lamda
for m= 1
t1 = lamda/2n = 520 nm/2(2.62 = 99.23 nm
t2 = 2 lamda/2n = 2(520 nm/2(2.62 = 198.47nm
t3 =3 lamda/2n =3* 520 nm/2(2.62 = 297.69nm
t4 =4 lamda/2n =4* 520 nm/2(2.62 = 396.92 nm
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