The voltage source in the circuit has a potential difference epsilon = 5.0 V. An

Question

The voltage source in the circuit has a potential difference epsilon = 5.0 V. An ammeter reads a current I at point A, and the bulb has a resistance R = 5 ohm. What is the current at point D? What is the potential difference read between points B and C? What is the power dissipated in the bulb? A 10-ohm bulb is added to the circuit as shown below. What is the current at A? What is the potential difference read between points 3 and C? What is the power dissipated in each bulb? How does the brightness of the bulb between B and C compare to its brightness in Figure 1? Determine the ratio of the power of that bulb in Figure 2 to its power in Figure 1. The bulbs are now rearranged as shown below. What is the current at A? What is the potential difference read between points B and C? What is the power dissipated in each bulb

Explanation / Answer

here,

E = 5 V

R = 5 ohm

1)

current at point D , I = E/R = 5/5

I = 1 A

2)

the potential difference between B and C , V = I * R

V = 5 * 1 = 5 V

3)

the power dissapated to the bulb , P = V * I

P = 5 W

4)

when R' = 10 ohm is added

Req = R * R' /( R + R')

Req = 3.33 ohm

the current at A , I' = E /Req

I' = 5/3.33 = 1.5 A

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