4/5/2016 11:00 PM A 25/100 4/5/2016 08:13 PM Gradebook Print Calculator Periodic

Question

4/5/2016 11:00 PM A 25/100 4/5/2016 08:13 PM Gradebook Print Calculator Periodic Table Question 9 of 16 Map pling A 250-g weight is tied to a piece of thread wrapped around a spool, which is suspended in such a way that it can rotate freely. When the weight is released, it accelerates toward the floor as the thread unwinds. Assume that the spool can be treated as a uniform solid cylinder of radius R 4 cm and mass Ms 100 g. Find the tension in the thread and the magnitude of the acceleration of the weight as it descends. Assume the thread has negligible mass and does not slip or stretch as it unwinds. R 4 cm. Number M 100 g acceleration Number tension mw 250 g O Previous & Give Up & View Solution 2 Check Answer Next Ext Hint

Explanation / Answer

given data

M = 0.250 kg
m = 0.100 kg

from rotational dynamics

moment of inertia is Is = k*mR² where k = 0.5

we can write the formula for acceleration is

a = g[1 - 1/(M/km + 1)]

M/km + 1

(0.250/(0.5*0.1))+1 =6

a= 9.8*(1-1/6) = 8.166 m/s^2

tension in the cable

T = M*(g - a)

T=0.250*(9.8-8.166)

T=0.4085 N

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