. The voltage across the capacitor at time t = 0. V_c = The voltage across the r
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Question
. The voltage across the capacitor at time t = 0. V_c = The voltage across the resistance at time t = 0 V_R = The current at time t = 0.V_R = The time constant of the circuit, t = 0, I_0 = The voltage across the resistance at a time of one time constant V_R = The voltage across the capacitor at a time of one rime constant V_c = The current at a time of one time constant I = The voltage across the resistance at t = 100 mu s. V_R = The voltage across the capacitor at t = 100 mu s. V_C = The current at t = 100 mu s. I =.Explanation / Answer
(a)
When switch is closed, Capacitor acts as a short circut.
Therefore Voltage across the capacitor = 0.
(b)
As Capacitor acts as a short circut, Voltage across the Resistor = Battery Voltage.
Voltage across the Resistor = 400 V
(c)
Current at time t = 0,
I = V/R
I = 400/25000
I = 0.016 A
(d)
Time constant of the circut, t = R*C
t = 25 * 10^3 * 0.1*10^-6 s
t = 0.0025 s
(c)
(d)
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