You know your process squires 20 liters of toluene during each 8-hour shift. All

Question

You know your process squires 20 liters of toluene during each 8-hour shift. All of this material is released into the workroom air. What is the generation rate, in mg/min? If the generation rate for a contaminant is 12 mg/min and the dilution flow rate is 2,000 CFM, what is the equilibrium concentration of the contaminant, in mg/m^3? This is very easy. The equilibrium concentration, C_eq, is the generation rate, G, divided by the volume flow rate, Q. C_eq = G/Q = 12mg/min/2000ft^3/min (0.0353 ft^3/l)(10^3l/m^3) = 0.212/m^3

Explanation / Answer

density of toluene=867 kg/m3

mass=density*volume = 867*20/1000 kg =17340000 mg

time=8 hour=8*60=480 min

gen. rate=mass/time = 17340000/480=36125 mg/min

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