A nervous diver stands at rest at the end of a 31 kg diving board as shown in th

Question

A nervous diver stands at rest at the end of a 31 kg diving board as shown in the figure. If the mass of the diver is 137 kg and the board is 3.7 m long, what is the net torque exerted on the diving board due to gravity about the fixed end of the board? Assume the mass of the board is uniformly distributed, and be sure to include the proper sign for the torque. Calculate the torque due to the diver's weight (at the end of the board) and the torque due to the board's weight (at its center), and add them together. Be careful with the sign!

Explanation / Answer

m =31kg , M =137 kg , L =3.7 m

Torque = rxF

net torque about an axis passing through fixed point is

Net Torque = -(m*g*L/2) - (M*g*L) = -(31*9.8*3.7/2) -(137*9.8*3.7)

= - 5529 N.m (negative sign is in answer)

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