Problem 2 A disk of radius R and mass M= 10 g is rotating freely about a fixed a
ID: 1456364 • Letter: P
Question
Problem 2 A disk of radius R and mass M= 10 g is rotating freely about a fixed axis through its center with angular velocity o-11 rad/s. A spider of mass m = 0.5 g descends onto the disk and goes along for the ride. The moment of inertia of the disk is 1 = (l/2)MR2 (a) Which principle will allow you to calculate the angular velocity after the spider has landed? (b) Calculate the angular velocity after the spider has landed on the disk. (c) If the spider starts crawling towards the center of the disk, the angular velocity is going to [I] increase, [2] decrease, or [3] remain the same. Give a short explanation for your answer.Explanation / Answer
1. a) Principle of Conservation of Angular momentum
b) Initial angular momentum = 0.5MR^2 * w
Final angular momentum = (0.5MR^2 + mR^2) * w'
From conservation of angular momentum
0.5MR^2 * w = (0.5M + m)R^2 * w'
0.5*0.01*R^2 * 11 = (0.005+0.0005)R^2 *w'
w' = 10 rad/s
c) If the spider starts crawloing, inwards, the moment of inertia of the system would decrease, hence increasing the angular velocity of the system
3. A) Translational KE = 0.5Mv^2
Rotational KE = 0.5Iw^2
for same M, R and v, both have same ke
hence [1] only (i)
B) [2] conservation of mechanical energy
C) Total ME initially = 0.5*Mv^2 + 0.5Iw^2 = 0.5Mv^2 + 0.25MR^2*(v/R)^2 = 0.75Mv^2
Final Hieght = h
Using conservation of energy
Mgh = 0.75Mv^2
h = 0.75*4/10 = 0.3 m
D) Total ME initially = 0.5*Mv^2 + 0.5Iw^2 = 0.5Mv^2 + 0.5MR^2*(v/R)^2 = Mv^2
Final Hieght = h
Using conservation of energy
Mgh = Mv^2
h = 4/10 = 0.4 m
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