Equipotential surfaces are shown in the diagram at right. Explain all answers. I
ID: 1456649 • Letter: E
Question
Equipotential surfaces are shown in the diagram at right. Explain all answers. If the proton were placed at point P, how would it move How much net work would be required to move the proton form point P to point R How much energy would the proton acquire or lose if allowed to move form P to the shell it would travel to spontaneously The value of capacitor C in the diagram is muF. The potential difference across C is 10V. Find the equivalent capacitance between points C and D. Find the charge on the top 2 muF capacitor In the Circuit the battery has a voltage of 10V. Find the equivalent resistance of theExplanation / Answer
Here ,
a) as the electric field points in the direction of decreasing the potential .
hence, the direction of electric field is radially outwards
as the proton is positively charged
the direction of force on the proton is radially outwards
the proton will move radially outwards.
b)
net work required to move from P to R = (VR - VP) * e
net work required to move from P to R = (100 - 80) * 1.602 *10^-19
net work required to move from P to R = 3.204 *10^-18 J
c)
energy from point P to shell
energy from point P = VP * e
energy from point P = 80 * 1.602 *10^-19 J
energy from point P = 1.282 *10^-17 J
hence , 1.282 *10^-17 J is needed for the proton to move from P spontaneously.
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a) for 2 uF and 2 uF and C in series
1/C1 = 1/2 + 1/2 + 1/8
C1 = 0.275 uF
for C1 and 3 uF in parallel
Cp = C1 + 3
Cp = 3.275 uF
the capacitance between C and D is 3.275 uF
b) for the top 2 uF
charge on the 2 uF capacitor = V * C1
charge on the 2 uF capacitor = 10 V* 0.275 uF
charge on the 2 uF capacitor = 2.75 uC
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