You want to hang a 9.0-kg sign that advertises your new business. To do this, yo

Question

You want to hang a 9.0-kg sign that advertises your new business. To do this, you use a pivot to attach the base of a 3.0-kg beam to a wall (Figure 1) . You then attach a cable to the beam and to the wall in such a way that the cable and beam are perpendicular to each other. The beam is 2.5 m long and makes an angle of 37? with the vertical. You hang the sign from the end of the beam to which the cable is attached.

Part B

Determine the horizontal and vertical components of the force exerted by the pivot on the beam.

Enter your answers numerically separated by a comma.

Explanation / Answer

As the beam is in equilibrium, net force and net torque acting on the beam must be zero.

Let T is the tension in te string.

Apply, Net torque about = 0

T*2.5*sin(90) - 9*9.8*2.5*sin(37) - 3*9.8*1.25*sin(37) = 0

T = (9*9.8*2.5*sin(37) + 3*9.8*1.25*sin(37))/2.5

= 61.93 N

Let Fx and Fy are forces exerted by pivot on the beam.
Now Apply Fnetx = 0

Fx - T*cos(37) = 0

Fx = T*cos(37)

= 61.93*cos(37)

= 49.46 N <<<<<<<<<<<-------------Answer

now Apply, Fnety = 0

Fy + T*sin(37) - 9*9.8 - 3*9.8 = 0

Fy = 9*9.8 + 3*9.8 - 61.93*sin(37)

= 80.33 N <<<<<<<<<<<-------------Answer

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.