ou are given a bottle of dry NaCi, In your own words, wite a brief description (

Question

ou are given a bottle of dry NaCi, In your own words, wite a brief description (1-2 paragraphs) of uire required to make goo mL of a 0 5M NaCi solution The formula weight of NaCi is 584 the procedure Write the description as if you were teaching to your classmate how showing the necessary calculations and including the units and correct measuring devices would need to make it properly from start to finish. to make this solution in the lab. that they 2. You are given a 2 M NacLstock solution. In your own words, write a brief description (1-2 paragraphs) of the procedure required to make 10 mL each of the following NaCI concentrations: 05M 10 M and 1.5 M Write the description as if you were teaching to your classmate how to make these solutions in the lab showing the necessary calculations and including the units and correct measuring devices that they would need to make them properly from start to finish. 3. Draw neatly on graph paper or use a graphing program like Excel to create a scatter plot with KMnO concentration as the X-axis and Asso as the Y-axis Your goal is to create one graph with two scatter plots: one for the parallel dilutions and another for the serial dilutions You will not graph the absorbance of the unknown dilution Notice that some of the dilution concentrations are mM, while others are . Be sure to convert the concentrations so that all of them are mM or You will also have to arrange your serial dilutions from smallest to largest concentration before entering them into the graph (the reverse order of the way you made them).

Explanation / Answer

First of all we want know that what is molarity?

Molarity = numbers of moles of solute in 1liter of solution

So that to make 0.5M solution

Calculations:-

For 1M NaCl Solution we have to add 58.4 gram of dry NaCl in 1 liter of water

Therefore

1=58.4, then

                       0.5=X , therefore

X= 58.4*0.5/1=29.2

To make 0.5 M solution we have to add 29.2 gram of NaCl in 1 liter of water, here we have to make 900ml

So that

For 1000ml= 29.2gm , then for

900ml=X gm

So X = 29.2*900/1000= 26.28 gm

To make 900ml of 0.5 M solution we have to add 26.28 gram of NaCl in 900ml.

We have to make 10 ml of 0.5M, 1.0M AND 1.5M SOLUTION

WE CAN USE FORMULA

C1V1=C2V2

C1=2, V1=? V2=10, C2=0.5

So V1= C2V2/C1

V1= 0.5*10/2=2.5 we have to add 2.5 ml stock solution in7.5ml of water

For 1.0 M

C1V1=C2V2

V1=1*10/2=5 we have to add 5ml of stock solution in 5 ml of water

For 1.5M

C1V1=C2V2

V1= 1.5*10/2 = 7.5 we have to add 7.5ml stock solution in 2.5 ml of water.

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