(20%) Problem 5: A hockey puck has a velocity of v = vxi + vyj. Another puck wit

Question

(20%) Problem 5: A hockey puck has a velocity of v = vxi + vyj. Another puck with identical mas s is at rest at the origin. The two pucks collide. After the collision it is observed that the second puck has a velocity of vf = v2yj. Randomized Variables 33% Part (a) Write an expression for the first pucks velocity after the collision, in terms of the variables in the problem statement and the unit vectors and j. Part (b) What is the magnitude of the first puck?s velocity, in meters per second, after the collision? Part (c) At what angle theta does this velocity make with respect to the x-axis, in degrees?

Explanation / Answer

initial momentum

Pi = m1*v

final momentum Pf = m1*v1f + m2*v2f

from momentum conservation

Pf = Pi

m1*v1f + m2*v2f = m1*v

m1 = m2 = m

v1f = v - v2f

(b)

v = 3.1i + 3.1 j

v2f = 1.7 j

v1f = 3.1i + 3.1j - 1.7 j

v1f = 3.1 i + 1.4 j

magnitude = sqrt(3.1^2+1.4^2) = 3.4 m/s

part(c)

direction = tan^-1(1.4/3.1) = 24.3 degrees

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