Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

ust35nc.theexpertta.com WileyPlus WebAssign The Expert TA Calculus IlI Chegg 49e

ID: 1459241 • Letter: U

Question

ust35nc.theexpertta.com WileyPlus WebAssign The Expert TA Calculus IlI Chegg 49er Express Moodle 2 UNCC Football!! Home Home Student: ndowdyl@unce.adu My Account Log Out Class Management 1 Help Exam #2 Begin Date: 1 1/6/2015 12:01:00 AM .. Due Date: 1 1 S.201 5 1 1 :59:00 PM End Date: 1 1/8/21 :00 PM (13 %) Problem 2: A student jumping on a trampoline reaches a maximum height of As I 6 m. The maximum height is measured from the surface of trampoline in its unstretched position. The student has a mass of m Randomized Variables h=1.66 m 71 kg. m=71kg 50% Part (a) what is the student's speed immediately before she reaches the trampoline after the jump in me? 50% Part (b) If, when she lands on the trampoline, she stretches the trampoline down d:0.75 m, what is the spring constant k in Nm of the trampoline? Grade Summary Deductions 0% Pittial 100% k=14106.77 sin0 tan() |-( coso cotan asinO acos0 atano acotan) sinh0 Amempts semaining detailed view IND ODegrees Radians Hints: Fendback

Explanation / Answer


part A: V^2 = 2 gh

V^2 = 2* 9.8* 1.66

V = 5.7 m/s

part B:

0.5 kx^2 = mgh

here

m is mass

g is accleration due to gravity

K is spring constant

x is compression


K = 71 * 9.8 *1.66/(0.5 * 0.75 * 0.75)

K = 4106.67 N/m