A 1.15-m-long metal bar is pulled to the right at a steady 5.0 m/s perpendicular

Question

A 1.15-m-long metal bar is pulled to the right at a steady 5.0 m/s perpendicular to a uniform. 0.740-T magnetic field. The bar rides on parallel metal rails connected through R = 26.0-ohm as shown in the figure (Figure 1). so the apparatus makes a complete circuit. You can ignore the resistance of the bar and the rails. Part A Calculate the magnitude of the emf induced in the circuit. Express your answer using two significant figures. Part B Find the direction of the current induced in the circuit. Part C Calculate the current through the resistor. Express your answer using two significant figures.

Explanation / Answer

Here ,

length of rod , L = 1.15 m

speed ,v = 5 m/s

magnetic field , B = 0.74 T

a) induced emf = B*v*L

induced emf = 1.15 * 5 * 0.74

induced emf = 4.255 V

the induced emf is 4.255 V

b) as the flux in loop is increasing

Using Lenz's law ,

direction of current is counter clockwise

c)

current = emf/R

current = 4.255/26

current = 0.164 A

the current in the resistor is 0.164 A

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