seesaw problem Consider the diagram below of a seesaw of length L with two block

Question

seesaw problem

Consider the diagram below of a seesaw of length L with two blocks fixed onto itas shown. The vertical dashed line marks the center of the seesaw as well as the midpoint (L? = L/2) to the two blocks. Assume the larger box (located at L? = 0) has twice the mass of the smaller box (located at L? = L). Approximately, where would you position the wedge such that the seesaw would be balanced (i.e., choose the letter that corresponds to the correct position on the wedge)? Note: this position on the wedge is given by L? in terms of the total length L of the wedge. A. A: L? = 0 B. B: L? = L/4 C. C: L? = L/2 C D. D: L? = 3L/4 E. E: L?=L

Explanation / Answer

Apply the equilibrium torques condition,

The product of distance and the force ( here weight ) of both objects should be same about equilibrium point

L'( 2m) g = L mg

2L' = L

L' = L /2

Thus, the correct option is ( c )

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