Suppose a flat roof has a surface area of 1.02000×10 2 m 2 . Presume the air ins

Question

Suppose a flat roof has a surface area of 1.02000×102 m2. Presume the air inside the building (and under the roof) is at atmospheric pressure, 1.01325×105 Pa, and that the air racing across the top of the roof is at a pressure of 1.00394×105 Pa.
a.)What is the force with which the air inside the house pushes the roof upward? (please calculate this to 5 significant digits)

b.)What is the force with which the air outside the house pushes the roof downward? (again, calculate this value to 5 significant digits)

c.)The lift force takes into account the combination of these two forces. What is the lift force acting on the roof?

Please provide steps/explanations as well! Thank you!

Explanation / Answer

a)
F inside = P inside * A
                  = 1.01325*10^5 * 1.02000*10^2
                  =1.0335*10^7 N
Answer: 1.0335*10^7 N

B)
F outside = P outside * A
                  = 1.00394*10^5 * 1.02000*10^2
                  =1.0240*10^7 N
Answer: 1.0240*10^7 N

C)
Lift = F inside - F outside
        = 1.0335*10^7 N - 1.0240*10^7 N
        = 95000 N
Answer: 95000 N

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