Each of two long straight parallel wires 11 cm apart carries a current of 100 A
ID: 1461088 • Letter: E
Question
Each of two long straight parallel wires 11 cm apart carries a current of 100 A. The figure shows a cross section, with the wires running perpendicular to the page and point P lying on the perpendicular bisector of the line between the wires. Find the magnitude and direction of the magnetic field at P when the current in the left-hand wire is out of the page and the current in the right-hand wire is also out of the page.
What is the magnitude of B?
What is the value of Bx?
What is the value of By?
What is the value of Bz?
Find the magnitude and direction of the magnetic field at P when the current in the left-hand wire is out of the page and the current in the right-hand wire is into the page. What is the magnitude of B?
What is the value of Bx?
What is the value of By?
What is the value of Bz?
Explanation / Answer
A)
Distance from each wire to poitn P, r = d/sqrt(2)
= 11/1.414
= 7.8 cm
= 0.078 m
Here, B1 = B2 = B = mue*I/(2*pi*r)
= 4*pi*10^-7*100/(2*pi*0.078)
= 2.56*10^-4 T
angle between B1 and B2 is 90 degrees
so, Bnet = sqrt(2)*B
= sqrt(2)*2.56*10^-4
= 3.62*10^-4 T <<<<<<-----------Answer
B) Bx = -Bnet = -3.62*10^-4 T
C) By = 0
D) Bz = 0
E) Bnet = 3.62*10^-4 T
F) Bx = 0
G) By = Bnet = +3.62*10^-4 T
H) Bz = 0
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.