2. An open-top 20.0[in] tall cylindrical tank is filled with water as shown belo

Question

2. An open-top 20.0[in] tall cylindrical tank is filled with water as shown below. A small puncture on the side of the tank, is located just 15 .0[mJ above round. The flow rate out of the tank is 1.00 [lt/min]. a) How fast is the water flowing through the hole? b) If the radius of the cylindrical tank is 10.0[m], what is the size of the hole? c) How far from the edge of the tank is the puddle? d) If we want punch another hole, closer to the ground. and get the new stream to land in the same puddle. how height should we do it?

Explanation / Answer

Here ,

a) height below the top of tank ,

h = 20 - 15

h = 5 m

speed of flow = sqrt(2 * g * h )

speed of flow = sqrt(2 * 9.8 * 5)

speed of flow = 10 m/s

the speed of flow is 10 m/s

b)

let the size of hole is A m^2

speed * area = volume flow rate

10 * A = (1 * 10^-3 m^3/60 s )

A = 1.683 *10^-6 m^2

the area of hole is 1.683 *10^-6 m^2

c)

time of flight , t = sqrt(2 * h/g)

t = sqrt (2 * 15/9.8)

t = 1.75 s

distance of puddle = 1.75 * 10
distance of puddle = 17.5 m

the distance of puddle fromthe edge of tank is 17.5 m

d) for the same range as

Height from ground = H - h

Height from ground = 20 - 5

Height from ground = 15 m

new hole must be 5 m above the ground

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