If I shoot a lead bullet with a mass of 5.0 g, it\'s temperature increases by 14

Question

If I shoot a lead bullet with a mass of 5.0 g, it's temperature increases by 145'C as it is stopped in a block of wood. How fast was the bullet going before it hit the block, assuming no energy loss besides heat? If I shoot a lead bullet with a mass of 5.0 g, it's temperature increases by 145'C as it is stopped in a block of wood. How fast was the bullet going before it hit the block, assuming no energy loss besides heat? If I shoot a lead bullet with a mass of 5.0 g, it's temperature increases by 145'C as it is stopped in a block of wood. How fast was the bullet going before it hit the block, assuming no energy loss besides heat?

Explanation / Answer

Let the bullet was travelling with a speed of 'v' before hitting the block.

Kinetic energy of the lead bullet is converted to the heat which raised its temperature.

So,

mv2/2 = mCleadT

=> v = [2CleadT]1/2 = (2 * 128 * 145]1/2 = 192.7 m/s

(Note: Use the specific heat value in J/kg since Joule contains kg as the unit of mass which is coherent in J/kg)

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