The units and correct significant figures 9) A thin lens in a certain position i
ID: 1462201 • Letter: T
Question
The units and correct significant figures 9) A thin lens in a certain position is shown to cause and inverted image 5.31cm. The original height was 2.00cm. number of significant figures. SHOW ALL OF YOUR CALCULATIONS, OR YOU WILL NOT GET CREDIT. M = . Find the magnification m. sure your answer contains the correct units and object 31m from the last problem, the image distance was measured at 26.2 cm. Calculate the Make sure your answer contains the correct units and number of significant object distance. figures. SHOW ALL OF YOUR CALCULATIONS, OR YOU WILL NOT GET CREDIT, M =-4, a 2·66 R Use the results from the previous problem to calculate the focal length of the lens. Make sure your answer contains the correct units and number of significant figures. SHOW ALL OF YOUR CALCULATIONS, OR YOU WILL NOT GET CREDIT. ( 1/do+1/d,=1/f) 11) a.a 2. 12) Is the image in this problemreal pr virtual?Explanation / Answer
( 9 )
Inverted images have negative image heights and therefore negative magnification values.
M = hi / ho = - 5.31 cm / 2.00 cm = - 2.66
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( 10 )
The magnification of an image is both the hi / ho ratio and the -di / do ratio.
M = -di / do = - 2.66
Write 26.2 cm for image distance di and solve for do
do = 10.0 cm
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( 11 )
Use lens equation
1 /f = 1/ u + 1/ V
= 1/ 10.0 cm + 1 / 26.2 cm
Solve for focal length
f = 7.25 cm
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