a Print A Calculator - Periodic Table Question 6 of 10 incorrect Incorrect Map o

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a Print A Calculator - Periodic Table Question 6 of 10 incorrect Incorrect Map on sapling learning As part of a carnival game, a 0.478-kg ball is thrown at a stack of 25.3-cm tall, 0.423-kg objects and hits with a perfectly horizontal velocity of 10.8 m/s. Suppose the ball strikes the topmost object as shown to the right Immediately after the collision, the ball has a horizontal velocity of 4.35 m/s in the same direction, the topmost object now has an angular velocity of 2.83 rad/s about its center of mass and all the objects below are undisturbed. If the object's center of mass is located 17.7 cm below the point where the ball hits, what is the moment of inertia of the object about its center of mass? Number .193 kgm hat is the center of mass velocity of the tall object immediately after it is struck? Number .331 m / S Incorrect Explanation Previous 9 Give Up & View Solution FE Try Again O Next > Exit

Explanation / Answer

velocity of centre of mass can be calculated by using conservation of momentum
initial momentum = final momentum
m1*v1i = m1*v1 + m2*v2f
0.478*10.8 = 0.478*4.35 + 0.423*vf
vf = 7.29 m/s
Answer: 7.29 m/s

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