Exercise 10.10 A cord s wrapped around the rim of a solid uniform wheel 0.22 m i
ID: 1462306 • Letter: E
Question
Exercise 10.10 A cord s wrapped around the rim of a solid uniform wheel 0.22 m in radius and of mass 8.60 kg . A steady horizontal pull of 50.0 N to the right is exerted on the cord, pulling it off tangentially from the wheel. The wheel is mounted on frictionless bearings on a horizontal axle through its center. Part A Compute the angular acceleration of the wheel |alpha|= Part B Compute the angular acceleration of the part of the cord that has already been pulled off the wheel. |a|= m/s^2 Part C Find the magnitude of the force that the axe exerts on the wheel. F=_____ N Part D Find the direction of the force that the axle exerts on the wheel. Phi= Phi degree below the horizontal, away from the direction of the pull on the cord. Part E degree below the horizontal, away from the direction of the pull on the cord. Which of the answers in parts (A), B), (C) arid ID) would change if the pull were upward instead of horizontal? (A), (B), (C) and (D) (A) and B) (C) and (D) (A)and(D)Explanation / Answer
A]
Total torque, =I*
moment of inertia, I=m*r2/2
50*r = 8.60*r2* / 2
= 100 / (8.60*0.220)
= 52.85 rad/s2
B] magnitude of acceleration = 52.85*0.220 = 11.63 m/s2
C] magnitude of Force = sqrt(502+[8.62*9.812]) = 98 N
D) Direction of the force that the axel exerts on the wheel = tan-1([8.6*9.81]/[2*50]) = tan-1[84.37 / 100]
40.15o below horizontal
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