A. What direction does the induced current flow through the resistor, up or down
ID: 1463029 • Letter: A
Question
A. What direction does the induced current flow through the resistor, up or down? B. Derive an equation for the current that runs through the resistor in terms of the variables given in the figure. C. Find the electrical power dissipated by the resistor. D. Assume that the rails and rod are perfect conductor with zero resistance. What force must be exerted on the rod in order to move it to the right with a constant velocity? E. Now assume that the rod is moved to the left with a constant velocity, repeat a-d.Explanation / Answer
A)
down
B)
magnetic flux = B*A = B*l*dx
emf = rate of change in flux = B*l*dx/dt
current = i = emf/R = B*l*dx/(R*dt) = B*l*v/R <<<<<<<---------answer
(C)
power = i^2*R = B^2*l^2^v^2/R
(d)
Fb = i*l*B = B*l*v*l*B/R = B^2*l^2*v/R
++++++++++++++++++++++
E)
A)
upwards
B)magnetic flux = B*A = B*l*dx
emf = rate of change in flux = B*l*dx/dt
current = i = emf/R = B*l*dx/(R*dt) = B*l*v/R <<<<<<<---------answer
(C)
power = i^2*R = B^2*l^2^v^2/R
(d)
Fb = i*l*B = B*l*v*l*B/R = B^2*l^2*v/R
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