A farmer owns a well that is 210 feet deep. He wants to pump 960 gallons of wate
ID: 1463075 • Letter: A
Question
A farmer owns a well that is 210 feet deep. He wants to pump 960 gallons of water per minute to the surface. The pressure at the surface must be 43 psi to operate his center pivot. How much horsepower will be needed from his irrigation power unit? (Note: Power = pressure x flow rate)
Power = [Num]horsepower
A farmer owns a well that is 210 feet deep. He wants to pump 960 gallons of water per minute to the surface. The pressure at the surface must be 43 psi to operate his center pivot. How much horsepower will be needed from his irrigation power unit? (Note: Power = pressure x flow rate)
Power = [Num]horsepower
Explanation / Answer
volume = 960 gallons = 3.63 m^3
time = t = 1 min = 60 s
flow rate = V/t = 3.63/60
pressure = 43 psi = 2.96*10^5 Pa
power = P*V/t = 2.96*10^5*3.64/60 = 17957.33 W
1 horse power = 746 watts
power = 17957.33/746 = 24.1 hp <<<,,,------answer
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.