Use the following to answer questions 19-21: A 2.0-kg pistol fires a 1.0-g bulle

Question

Use the following to answer questions 19-21: A 2.0-kg pistol fires a 1.0-g bullet with a muzzle speed of 1000 m/s. The bullet then strikes a 10-kg wooden block resting on a horizontal frictionless surface. The block and the embedded bullet then slide across the surface. What is the kinetic energy of the bullet as it travels toward the block? The explosive charge in the pistol acts for 0.001 s. What is the average force exerted on the bullet while it is being fired? What is the speed of the "bullet + block" system immediately after the bullet is embedded in the block?

Explanation / Answer

1) bullet kinetic energy = 1/2mv^2 = 1/2*0.001*10^6 = 500J

2) force = ma

v = u+at

a = v/t = 1000/0.001 = 10^6 m/s^2

F = 0.001*10^6 = 1000 m/sec^2

3) from conservation of linear momentun

v = m1u1+m2u2/(m1+m2)

v = m1u1/(m1+m2) = 0.001*1000/10.001 = 0.099 m/sec

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