Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Question 1 Fused quartz possesses an exceptionally low coefficient of linear exp

ID: 1464254 • Letter: Q

Question

Question 1

Fused quartz possesses an exceptionally low coefficient of linear expansion, 5.50 × 10-7 (C°)–1. Imagine you had a bar of fused quartz of length 3.15 m at 20.0°C. By how much, in millimeters, would the bar expand if you heated it to 207°C?

question 2

You heat a 595 cm3 sample of a substance from 131°C to 277°C and find that its volume increases by 2.05 cm3. Calculate the coefficient of volume expansion of this substance.

Question 3

If you have 0.401 m3 of water at 25.0°C and add 0.137 m3 of water at 95.0°C, what is the final temperature of the mixture? Use 1000 kg/m3 as the density of water at any temperature.

question 4

A hot lump of 31.0 g of copper at an initial temperature of 80.2 °C is placed in 50.0 mL of H2O initially at 25.0 °C and allowed to reach thermal equilibrium. What is the final temperature of the copper and water given that the specific heat of copper is 0.385 J/(g·°C)? Assume no heat is lost to surroundings.

question 5

How much heat would be needed to completely evaporate 47.5 g of boiling water at a temperature of 100 °C? Express your answer in units of joules.

question 6

The temperature of a sample of copper increased by 22.9 °C when 257 J of heat was applied. What is the mass of the sample? give this information below:

Substance specific heat (j/(g degree x C)

lead 0.128

silver 0.235

copper 0.385

iron 0.449

aluminum 0.903

mass of the sample =?g

Explanation / Answer

Given,

Lo = 3.15 m

T1 = 20 C

T2 = 207 C

coefficent of lineral expansion, alfa = 5.5*10^-7 C^-1

increase in length, delta_L = Lo*alfa*(T2-T1)

= 3.15*5.5*10^-7*(27 - 20)

= 1.21*10^-5 m

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote