A 0.430-kg hockey puck, moving east with a speed of 2.30 m/s , has a head-on col

Question

A 0.430-kg hockey puck, moving east with a speed of 2.30 m/s , has a head-on collision with a 0.930-kg puck initially at rest.

Part A

Assuming a perfectly elastic collision, what will be the speed (magnitude of the velocity) of each object after the collision?

Enter your answers numerically separated by a comma.

vlighter puck, vheavier puck = ___________ , ___________ m/s

Part B

What will be the direction of the lighter object after the collision.

West or East

Part C

What will be the direction of the heavier object after the collision.

West or East

Explanation / Answer

m1 =0.43 kg , u1 =2.3 m/s, m2 =0.93 kg , u2 =0

Part A:

From conservation of momentum

m1u1+m2u2 =m1v1+m2v2

(0.43*2.3)+0 = 0.43v1 +0.93v2

0.989 = 0.43v1 + 0.93 v2 ...(1)

For perfectly elastic collision

u1 -u2 =v2-v1

2.3 = v2 -v1 ..(2)

By solving (1) and (2) we get

v1 = -0.846 m/s

v2 = 1.454 m/s

velocity of lighter puck = 0.846 m/s

velocity of heavier puck =1.454 m/s

Part B:

West

Part C:

East

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