A circuit is constructed with six resistors and two batteries as shown. The batt

Question

A circuit is constructed with six resistors and two batteries as shown. The battery voltages are V1 = 18 V and V2 = 12 V. The positive terminals are indicated with a + sign, The values for the resistors are: R1 = R5 = 57 , R2 = R6 = 122 R3 = 47 , and R4 = 124 . The positive directions for the currents I1, I2 and I3 are indicated by the directions of the arrows.

1) What is V4, the magnitude of the voltage across the resistor R4?V

2) What is I3, the current that flows through the resistor R3? A positive value for the current is defined to be in the direction of the arrow.A

3) What is I2, the current that flows through the resistor R2? A positive value for the current is defined to be in the direction of the arrow.A

4) What is I1, the current that flows through the resistor R1? A positive value for the current is defined to be in the direction of the arrow.A

5) What is V(a) – V(b), the potential difference between the points a and b?

Explanation / Answer

R1 = R5 = 57 ,
R2 = R6 = 122 ,
R3 = 47 ,
R4 = 124
V1 = 18 V
V2 = 12 V

I2 = I1 + I3 ------1

I2 * R2 + I3 * R3 + V1 + I2*R6 = V2
I2 * 122 + I3 * 47 + 18 + I2*122 = 12
244*I2 + 47*I3 = - 6 ---------2

I2 * R2 + I1 * R1 + I2*R6 = V2
I2 * 122 + I1 * 57 + I2*122 = 12
244 * I2 + 57 I1 = 12 ---------3

Using eq 1,2 & 3 -

I1 = 0.1766 A
I2 = 0.0079 A
I3 = - 0.1687 A (-ve sign means the Current is in the direction, opposite to the direction shown.)

Va - Vb = I2 * R6
Va - Vb = 0.0079 * 122
Va - Vb = 0.964 Volt

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