A demonstrator is holding one end of an elastic string taut but steady. The righ
ID: 1465519 • Letter: A
Question
A demonstrator is holding one end of an elastic string taut but steady. The right end is attached to a wall. The string is composed of two parts: a light string connected to a heavier string as shown in the figure below. Ignore the effects of gravity in this problem. Briefly explain each of your answers.
A. How do the tensions in the two parts of the string compare?
The tension in the heavy part of the string is greater.
There is not enough information given to decide.
The tensions in the two parts of the string are the same.
The tension in the light part of the string is greater.
B. How do the speeds of wave propagation in the two parts of the string compare?
There is not enough information given to decide.
The speed of propagation is greater in the light part of the string.
The speed of propagation is the same in the two parts of the string.
The speed of propagation is greater in the heavy part of the string.
She now moves her hand up and down once quickly, sending a single pulse down the string as shown in the figure below.
When her pulse reaches the heavy part of the string, what will be the effect on that part of the string?
C. After the last bit of the pulse has reached the joining point, the heavy side of the string will display
A pulse of smaller width.
No pulse at all.
There is not enough information to decide.
A pulse of greater width.
A pulse of the same width.
D. How does the time it takes bits of matter on the heavy side of the string to go up and down compared to what it took the bits of matter on the light side of the string?
They will move up and down in the same amount of time on both sides of the string.
Since there is no pulse on the right, the question is meaningless.
They will move up and down faster on the light side of the string.
It is 0.
They will move up and down faster on the heavy side of the string.
There is not enough information to decide.
A second demonstrator with an equivalent apparatus now begins to move his hand up and down in an oscillatory pattern, sending pulses down the string as shown in the figure below. When his pulses reach the heavy part of the string, pulses will appear on that part of the string.
E. How will the frequency of the oscillation of the bits of matter on the heavy side of the string compare to what is was on the light side of the string?
There is not enough information to decide.
The frequency will be greater on the heavy side of the string.
The frequency will be the same on both sides of the string.
The frequency will be greater on the light side of the string.
F. How will the wavelength of the oscillation of the bits of matter on the heavy side of the string compare to what is was on the light side of the string?
The wavelength will be greater on the light side of the string.
The wavelength will be greater on the heavy side of the string.
The wavelength will be the same on both sides of the string.
There is not enough information to decide.
Explanation / Answer
A. How do the tensions in the two parts of the string compare?
The tensions in the two parts of the string are the same. This is because, in this problem is ignore the gravity, and the system is in balancing between the tension at both ends must be equal.
B. How do the speeds of wave propagation in the two parts of the string compare?
The speed of propagation is greater in the light part of the string. this is due to the speed of propagation of a string directly dependent on the portion of mass in motion, this means that the higher the mass movement will lower the speed of propagation.
C. After the last bit of the pulse has reached the joining point, the heavy side of the string will display
A pulse of the same width. it is not the elements of the mass of the string that be transported, if not the perturbation in the form produced by shaking at one end.
D. How does the time it takes bits of matter on the heavy side of the string to go up and down compared to what it took the bits of matter on the light side of the string?
They will move up and down in the same amount of time on both sides of the string. Remember that component y of the speed do not change and therefore does not change the time it goes down does not change bits of matter.
E. How will the frequency of the oscillation of the bits of matter on the heavy side of the string compare to what is was on the light side of the string?
The frequency will be the same on both sides of the string. If not change its time, not change its frecuency
F. How will the wavelength of the oscillation of the bits of matter on the heavy side of the string compare to what is was on the light side of the string?
The wavelength will be the same on both sides of the string.
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