Question 1) Two billiard balls of equal mass collide in the following manner. Wh

Question

Question 1)

Two billiard balls of equal mass collide in the following manner. What is the final velocity of ball B, and what is the speed and direction of ball A as it recoils?

Question 2)

Two balls collide in a totally inelastic collision. The first ball has twice the mass of the second. The first ball has velocity v (to the right), and the second has velocity ?v (to the left). What is the final velocity of the two balls after they collide? What was the % change in kinetic energy?

It's a homework problem worth 20 points and I'm not sure if my answer is correct. I said that both would have the same velocity because they are inelastic so i put m(v)+2m(-v)/2m*m= v3 but its probably wrong >.< and i have no idea how to find the % change in kinetic energy.

Please help!! Its urgent!!

Explanation / Answer

mlet m be tne mass of second ba

momentum along y axis = mvy = 2*2 m = 4 m kgm./s

momentum aomg x axis = Mvy = 3.7 m/s

net Momoentum P^2 = Px^2 + Py^2

P^2 = (4m)^2 + (3.7m)^2

Pfinal = 5.44 m

Final Velocity Vf = 5.44 m/(2m+m) = 1.816 m/s^2

---------------------------
part B :

KE i of A = 0.5 * m * 2^2 = 2 m

KE of i of B = 0.5* 2m * 3.7^2 = 13.69 m

KE t i = 2+ 13.69 = 15.69 m Joues

KE f = 0.5(m +2m) * 1.816^2

KEf = 4.94 m Joules

so Fractional Change of KE = KEf - Kei/)KEi

% KE change = (4.94 - 15.59)/(15.69)

= 67.8%

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.