Suppose that in the figure above, C1 = C2 = C3 = 17.1 ?F, and C4 = 31.3 ?F. The

Question

Suppose that in the figure above, C1 = C2 = C3 = 17.1 ?F, and C4 = 31.3 ?F. The circuit is assembled with the capacitors uncharged, after which a voltage is applied across points a and b such that the charge on C2 is Q2 = 12.9 ?C. The voltage source is then disconnected.

(A)What is the charge on C1?

(B)What is the voltage on C1?

(C)What is the voltage on C2?

(D)What is the voltage on C3?

(E)What is the voltage on C3?

(F)What is the charge on C3?
(G)What is the charge on C4?

(H)What is the voltage on C4?

(I)What is the voltage Vab across the entire combination?

Explanation / Answer

Here, Charge on C2 = 12.9 uC

we can see in diagram, capacitor C1 and C2 are in series combination,so charge on both will be same

(a) Charge on C1 = 12.9 uC

(b) Voltage on C1 = 12.9 * 10^(-6)/17.1 *10^(-6) =0.75 Volts

(c) Voltage on C2 = 0.75 V

(d) Voltage on C3 = 1.5 V

(e)

(f) Charge on C3 = 1.5*1.71 *10^(-6) = 25.65 uC

(g) Charge on C4 = 1.5*31.3 *10^(-6) = 46.95 uC

(H) Voltage on C4 = 1.5 V

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