Car on ramp Answer all parts, check units and tell me if the answers are right.
ID: 1466659 • Letter: C
Question
Car on ramp
Answer all parts, check units and tell me if the answers are right.
QUE STION 1 A A 1535 kg car is moving down a road with a slope grade of 10% at a constant speed of 13 m/s. What is the direction and magnitude of the frictional torce? (define positive in the forward direction, i.e., down the slope)? 9,768.78N B A 1.576 kg car is moving down a road with a slope grade of 11% while slowing down at a rate of 3 m s 2. hat is he direction and magnitude of th mo afro (define positive in the forward direction, i.e., down the slope)? -6,541N A 1 729 kg car is moving down a road with a slope grade o 23% while speeding up at a rate of 1.9 m/s 2. What is the d ection and magnitude of the frictional force? define positive in the forward direction, i.e., down the slope)? c. D. A 1952 kg car is moving down a road with a slope grade of 10% while speeding up at a rate of 3.2 m/s 2. What is the direction and magnitude of the frictional force? (define positive in the forward direction, i.e., down the slope)? 4,342.93N 4,342 93Explanation / Answer
Part D
as grade is the change in altitude over the length of run
the angle of the slope is
tan = 0.10
= 5.711°
The component of gravity acceleration acting parallel to the slope is
a = gsin
a = 9.81sin5.711
a =0.976 m/s²
so friction from the road on the tires must provide the additional acceleration of
3.2 - 0.976 = 2.224 m/s²
F = ma
F = 1952(2.224)
F = 4342 N downslope
Part A
We don't get to see everything you did so you may have to spot your mistake yourself.
Frictional force is negative and of magnitude F = 1535 × 9.81 × 0.10 = 1506 N.
Note that in mathematics gradient = tangent of the slope's angle to the horizontal; whereas on maps and road signs the gradient = sine of the slope's angle to the horizontal. In this case I would be inclined to say that the given gradient is already the sine of the angle and can therefore be entered directly into the calculation (as above).
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