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*****Please indicate answers clearly***** A baseball is thrown from the roof of

ID: 1466992 • Letter: #

Question

*****Please indicate answers clearly*****

A baseball is thrown from the roof of 20.1 m -tall building with an initial velocity of magnitude 11.3 m/s and directed at an angle of 50.3 degree above the horizontal. What is the speed of the ball just before it strikes the ground? Use energy methods and ignore air resistance. What is the answer for part (A) if the initial velocity is at an angle of 50.3 degree below the horizontal? If the effects of air resistance are included, will part (A) or (B) give the higher speed?

Explanation / Answer

a)

Initial energy = 1/2 m*v^2 = 0.5* m * 11.3^2

potential energy lost = m gh = m*9.8 * 20.1

so final energy = 0.5 *v^2 = 0.5 *11.3^2 + 9.8 *20.1

V2 = 22.83 m/s

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b) answer of part a doesn't change because we don't use any angle for conservation of energy

so V2 = 22.82 m//s

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c. pArt A will give higher sped