In the book. Manifold Destiny, the author Chis Maynard has recipes and direction
ID: 1467479 • Letter: I
Question
In the book. Manifold Destiny, the author Chis Maynard has recipes and directions for cooking food on the top of your engine motor. Many things are possible to cook this way. from hot dogs to "hobo pies to complete turkey dinners suitable for Thanksgiving. The engine gets hot. which is energy lost, that lost power is used to heat the food. Different foods require a different minimum amount of time to cook Suppose that in order to cook a hot dog. I need 46.3 kJ transferred into the hot dog. We're going to calculate the minimum amount of time needed to cook the dog. First we need to know how much power is going heat the dog. Suppose that the burning of the gasoline supplies your car with 144 kW, and that the engine is only 32.2% efficient. What is the power lost (Pl) from the engine? Next, how much of the lost power can be delivered to the hot dog. The power lost from the engine is power supplied to the hot dog Assume that 0.132% of that energy can be used to heat the dog. What is the amount of power (Pdog) that will heat the dog? Finally, now that we know the actual power amount that will heat the dog, we can calculate the minimum cooking time, tc, to heat the dog to a safe temperature. P dog = tc = Number kV Number kW Number minExplanation / Answer
(a).Power P = 144 kW
= 144 x10 3 W
Efficiency n = 32.2 %
= 0.322
Power utilized P ' = nP
= 46.368 kW
Power lost from engine P " = P - P '
= 97.632 kW
(b).Power supplied to the hot dog Pd = 0.132 % of P "
= (0.132/100) P"
= 0.12887 kW
(c).Required time t = E / P d
Where E = energy required to cook the hot dog
= 46.3 kJ
Substitute values you get t = 46.3 kJ /0.12887 kW
= 359.26 s
= (359.26 / 60) min
= 5.987 min
~ 6 min
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