Vectors A and B lie in the x-y plane. Vector A has a magnitude of 13.6 and is at

Question

Vectors A and B lie in the x-y plane. Vector A has a magnitude of 13.6 and is at an angle of 120.5° counter-clockwise from the x-axis. Vector B has a magnitude of 25.7 and is 240.3° from the x-axis. Resolve A and B into components, and express in unit vector form below.

Vectors A and B lie in the x-y plane. Vector A has a magnitude of 13.6 and is at an angle of 120.5° counter clockwise from the +x-axis. Vector B has a magnitude of 25.7 and is 240.3° from the +x-axis. Resolve A and B into components, and express in unit vector form below. Number Number Number Number Find the cross product. Number

Explanation / Answer

A = 13.6*cos(120.5)i + 13.6*sin(120.5) j

= -6.9 i + 11.72 j

B = 25.7*cos(240.3)i + 25.7*sin(240.3) j

= -12.73 i - 22.32 j

A cross B = (-6.9 i + 11.72 j) cross (-12.73 i - 22.32 j)

= -6.9*(-22.32) k + 11.72*(-12.73) (-k)

= 303.2 k

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