so i really need hepl with this question 2 but both answers appreciated 2. (7 po

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so i really need hepl with this question 2 but both answers appreciated

2. (7 points) Now let’s look at a similar situation, but moving away from rulers: Calvin (mass = 15kg) and his tiger, Hobbes, (mass = 5kg) are walking out on a 5-meter beam (mass = 40kg) balanced on two posts that are spaced 3 meters apart as shown. Calvin runs out to the very end of the beam. How close to the right edge of the beam can the tiger walk before the beam starts to tip? Hint: This is just like in lab. Draw your forces, FBD, and RBD. The beam starts to tip once the normal force of the left support on the beam goes to zero. Let me know if you need more hints…

(3 points) Say your meter ruler weighs 110g, and has uniform density. If you place the pivot 1/3 of the length from the end, and push down at the shorter edge with 3.5N. What force (and what direction) should you apply to the opposite end? 1. (7 points) Now let's look at a similar situation, but moving away from rulers: Calvin (mass 15kg) and his tiger, Hobbes, (mass 5kg) are walking out on a 5-meter beam (mass 40kg) balanced on two posts that are spaced 3 meters apart as shown. Calvin runs out to the very end of the beam. How close to the right edge of the beam can the tiger walk before the beam starts to tip? 2. Hint: This is just like in lab. Draw your forces, FBD, and RBD. The beam starts to tip once the normal force of the left support on the beam goes to zero. Let me know if you need more hints.. 3m

Explanation / Answer

1)Given,

m = 110 g = 0.11 kg ; F = 3.5 N

Let the required force be Fo at the opposite end.

we have dist of F from the pivot point = x = L/3

and that of Fo = r = 2L/3

For equilibrium to occur, the counterclokwise torque should be equal to the clokwise, so

F L/3 - m g L/2 - Fo 2L/3 = 0

Fo = 3(F/3 - mg/2)2 = 3(3.5/3 - 0.11 x 9.8)/2 = 0.133 N

Hence, Fo = 0.133 N.

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