6. Hughes and Roth isolated a mutation (nadD) in a gene in Salmonella. They did

Question

6. Hughes and Roth isolated a mutation (nadD) in a gene in Salmonella. They did two-factor crosses with phage P22 to determine the linkage data, draw a linkage map of the nadD, lip, and leus genes. [Indicate percent required for NAD biosynthesis map of nadD relative to the ip and leus genes. From the following tworfactor eros cotransduction and draw appropriate arrowheads.] (10 points) Selected Recombinantsumber phenotype NadD+i Donor Recipient obtained dD*ip dD in 53 57 D . .dDpLip uS 23 63 " Lip+ us

Explanation / Answer

The order of the genes is LeuS -------NadD --------Lip Cotransduction frequency = number of marker colonies / number of other colonies From the above values given cotransduction frequency between leuS --->Nad is 77% Nad----> Lip = (57/57+43) x100 = 57 % lip-----> nad = ( 47/47+53) x 100 =47 % leuS -----> lip = 37% ( 37/ 37 +63) = 37%

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